document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408099>Question 408099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of the perpendicular from R to KO when R (3 , 4), K ( 3 , 1) and O ( 8 , 4) are the vertices of a right-angled triangle.\r<BR>\n" );
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document.write( ":) =)\r<BR>\n" );
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document.write( "*Please answer as soon as possible. :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289512 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the length of the perpendicular from R to KO when R (3 , 4), K ( 3 , 1) and O ( 8 , 4) are the vertices of a right-angled triangle.\r<BR>\n" );
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document.write( "What you have here is a right triangle with legs of 5(RO) and 3(RK) and a hypotenuse (OK).<BR>\n" );
document.write( "Using the pythagorean theorem, OK = sqrt(5^2+3^2)=sqrt(34)<BR>\n" );
document.write( "Let x=length of the perpendicular from R to KO, and P, the point at which the perpendicular lands on KO.<BR>\n" );
document.write( "We can now see two similar triangles: the first is the larger one,RKO, and a smaller,RKP of which x is one of the legs. We can now set up a proportion.<BR>\n" );
document.write( "RO/KO=RP/RK<BR>\n" );
document.write( "5/sqrt(34)=x/3<BR>\n" );
document.write( "x=15/sqrt(34)<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "x=2.57 </SPAN>\n" );
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