document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44018>Question 44018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> inverse diviation, joint and combined, \r<BR>\n" );
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document.write( "The current I in an electrical conductor varies inversely as the resistance R of the conductor.  If the current is 1/2 ampere when the resistance is 240 omhs, what is the current when the resistance is 540 omhs?\r<BR>\n" );
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document.write( "please help set this up </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28951 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> current I in an electrical conductor varies inversely as the resistance R of the conductor. If the current is 1/2 ampere when the resistance is 240 omhs, what is the current when the resistance is 540 omhs? \r<BR>\n" );
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document.write( "I=k/R<BR>\n" );
document.write( "Need to find \"k\".<BR>\n" );
document.write( "(1/2)=k/240<BR>\n" );
document.write( "k=120<BR>\n" );
document.write( "So the equation for this problem is I=240/R\r<BR>\n" );
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document.write( "Now, what is the current when the resistance is 540?<BR>\n" );
document.write( "I=240/540<BR>\n" );
document.write( "I=4/9 amp.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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