document.write( "Question 412009: i have to write my own linear system problem for school and solve it by using elimination and substitution but when i tried solving it i got two different solutions
\n" ); document.write( "the equations are y=1500+20x and y=3000+10x
\n" ); document.write( "when i used substitution i got (150,4500)and with elimination i got (-300,-4500)
\n" ); document.write( "is that correct or wrong? \n" ); document.write( "

Algebra.Com's Answer #289462 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "Hm...the system of linear equations You have picked has only 'one' solution:
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document.write( "solving by substitution method
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document.write( "y=1500+20x and 
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document.write( "y=3000+10x
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document.write( "1500+2x = 3000+10x
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document.write( "1200 = 8x
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document.write( " 150 = x and y = 1500 + 3000 = 4500\r
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document.write( "solving by elimination method
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document.write( "y=1500+20x and 
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document.write( "y=3000+10x\r
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document.write( " y= 1500+20x and 
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document.write( "-y=-3000-10x    |multiplying 2nd equation thru by -1 and adding so as to eliminate y
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document.write( " 0 = -1500 +10x
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document.write( "1500 = 10x
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document.write( " 150 = x  and y = 1500 + 3000 = 4500\r
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document.write( "CHECKING our Answer(s)***
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document.write( "4500 = 3000 + 1500
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document.write( "4500 = 1500 + 3000
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document.write( "  \n" );
document.write( "

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