document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=412013>Question 412013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To get 90ml of a 35% sugar solution, a 65% solution is mixed with a 20% solution.  How much of the 65% solution is needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289459 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  To get 90ml of a 35% sugar solution, a 65% solution is mixed with a 20% solution. How much of the 65% solution is needed?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "sugar + sugar = sugar<BR>\n" );
document.write( "0.65x + 0.20(90-x) = 0.35*90<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "65x + 20*90 - 20x = 35*90<BR>\n" );
document.write( "45x = 15*90<BR>\n" );
document.write( "x = (1/3)*90<BR>\n" );
document.write( "x = 30ml (amt of 65% needed)<BR>\n" );
document.write( "90-x = 60ml (amt of 20% needed)<BR>\n" );
document.write( "===============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );