document.write( "Question 412009: i have to write my own linear system problem for school and solve it by using elimination and substitution but when i tried solving it i got two different solutions
\n" ); document.write( "the equations are y=1500+20x and y=3000+10x
\n" ); document.write( "when i used substitution i got (150,4500)and with elimination i got (-300,-4500)
\n" ); document.write( "is that correct or wrong?
\n" ); document.write( "

Algebra.Com's Answer #289458 by nerdybill(7384)\"\" \"About 
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\n" ); document.write( "Substitution method:
\n" ); document.write( "y=1500+20x
\n" ); document.write( "y=3000+10x
\n" ); document.write( ".
\n" ); document.write( "1500+20x=3000+10x
\n" ); document.write( "1500+10x=3000
\n" ); document.write( "10x=1500
\n" ); document.write( "x = 150
\n" ); document.write( ".
\n" ); document.write( "y=1500+20x
\n" ); document.write( "y=1500+20(150)
\n" ); document.write( "y=1500+3000
\n" ); document.write( "y=4500
\n" ); document.write( ".
\n" ); document.write( ".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Applying the elimination method to:
\n" ); document.write( "y=1500+20x
\n" ); document.write( "y=3000+10x
\n" ); document.write( ".
\n" ); document.write( "moving the x's to the left:
\n" ); document.write( "y-20x=1500
\n" ); document.write( "y-10x=3000
\n" ); document.write( ".
\n" ); document.write( "multiply the bottom equation by -1 to get add both together:
\n" ); document.write( " y-20x=1500
\n" ); document.write( "-y+10x=-3000
\n" ); document.write( "---------------
\n" ); document.write( "-10x = -1500
\n" ); document.write( "x = 150
\n" ); document.write( ".
\n" ); document.write( "substitute into top equation to find y:
\n" ); document.write( "y=1500+20x
\n" ); document.write( "y=1500+20(150)
\n" ); document.write( "y=1500+3000
\n" ); document.write( "y=4500\r
\n" ); document.write( "\n" ); document.write( "
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