document.write( "Question 411912: On a 130 mile trip from Orlando to Sarasota, Roberto encountered a heavy thunderstorm for the last 40 miles of the trip. During the thunderstorm he averaged 20 miles per hour slower than before the storm. The entire trip took 2 1/2 hours. How fast did he travel before the storm?\r
\n" ); document.write( "\n" ); document.write( "2.5(20-x)=?x
\n" ); document.write( "50-2.5x=?x \n" ); document.write( "
Algebra.Com's Answer #289443 by mananth(16946)\"\" \"About 
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total trip 130 miles
\n" ); document.write( "in storm 40 miles
\n" ); document.write( "..
\n" ); document.write( "ist leg 90 miles
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\n" ); document.write( "first leg speed =x
\n" ); document.write( "second leg speed = x-20 mph
\n" ); document.write( "..
\n" ); document.write( "90/x + 40/(x-20)=2 1/2 hours\r
\n" ); document.write( "\n" ); document.write( "90/x + 40/(x-20)=5/2
\n" ); document.write( "LCD = x(x-20)
\n" ); document.write( "multiply by x(x-20)
\n" ); document.write( "90(x-20)+40x=5x(x-20)/2
\n" ); document.write( "multiply by 2
\n" ); document.write( "180(x-20)+80x=5x^2-100x
\n" ); document.write( "180x-3600+80x=5x^2-100x
\n" ); document.write( "5x^2-360x+3600=0
\n" ); document.write( "/5
\n" ); document.write( "x^2-72x+720=0
\n" ); document.write( "x^2-60x-12x+720=0
\n" ); document.write( "x(x-60)-12(x-60)=0
\n" ); document.write( "(x-60)(x-12)=0
\n" ); document.write( "x= 60 mph speed before the storm\r
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