document.write( "Question 411908: I really had a problem on this, please help me.
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document.write( "A father is 6 times as old as his son and 3 times as old as his daughter. If the daughter is 5 years older than the son. how old is each.? \n" );
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Algebra.Com's Answer #289434 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let the father age is x years.\r \n" ); document.write( "\n" ); document.write( "son age= x/6 \r \n" ); document.write( "\n" ); document.write( "daughter age= x/3 \r \n" ); document.write( "\n" ); document.write( "and according to question \r \n" ); document.write( "\n" ); document.write( "x/3 = x/6 + 5\r \n" ); document.write( "\n" ); document.write( "=> x/3 - x/6 = 5 \r \n" ); document.write( "\n" ); document.write( "=> x/6 = 5 \r \n" ); document.write( "\n" ); document.write( "=> x = 30 years.\r \n" ); document.write( "\n" ); document.write( "father's age = 30 years, \r \n" ); document.write( "\n" ); document.write( "son's age = 30/6 = 5 years.\r \n" ); document.write( "\n" ); document.write( "daughter's age = 30/3= 10 years...\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |