document.write( "Question 411335: 9/4 log2(x)=3 \n" ); document.write( "
Algebra.Com's Answer #289433 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"%289%2F4%29log%282%2C+%28x%29%29=3\"
\n" ); document.write( "First, let's isolate the logarithm. Multiplying both sides by 4/9 we get:
\n" ); document.write( "\"%284%2F9%29%289%2F4%29log%282%2C+%28x%29%29=%284%2F9%293\"
\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"log%282%2C+%28x%29%29=4%2F3\"
\n" ); document.write( "With the log isloated we next rewrite the equation in exponential form. In general \"log%28a%2C+%28p%29%29+=+q\" is equivalent to \"p+=+a%5Eq\". Using this pattern on your equation we get:
\n" ); document.write( "\"x+=+2%5E%284%2F3%29\"
\n" ); document.write( "This may be an acceptable answer. However, a preferred form might be to rewrite this in radical form:
\n" ); document.write( "\"x+=+root%283%2C+2%5E4%29\"
\n" ); document.write( "which can be simplified:
\n" ); document.write( "\"x+=+root%283%2C+2%5E3%2A2%29\"
\n" ); document.write( "\"x+=+root%283%2C+2%5E3%29%2Aroot%283%2C+2%29\"
\n" ); document.write( "\"x+=+2%2Aroot%283%2C+2%29\"
\n" ); document.write( "
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