document.write( "Question 411318: Find the solution set in a +bi form: 6x^2 + 4x +1 =0\r
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Algebra.Com's Answer #289430 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Find the solution set in a +bi form: 6x^2 + 4x +1 =0
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\n" ); document.write( "\n" ); document.write( "6x^2 + 4x +1 =0
\n" ); document.write( "Use quadratic formula below:
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "with a=6,b=4,c=1
\n" ); document.write( "..
\n" ); document.write( "(-4+-sqrt(4^2-4*6*1))/2*6
\n" ); document.write( "=(-4+-sqrt(16-24))/12
\n" ); document.write( "=(-4+-sqrt(-8))/12
\n" ); document.write( "=(-4+-2*sqrt(-2))/12
\n" ); document.write( "=(-4+-2*sqrt(2)i)/12
\n" ); document.write( "=(-2+-sqrt(2)i)/6
\n" ); document.write( "=-2/6+-(sqrt(2)/6)i)
\n" ); document.write( "ans:
\n" ); document.write( "-2/6+(sqrt(2)/6)i)
\n" ); document.write( "or
\n" ); document.write( "-2/6-(sqrt(2)/6)i)\r
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