document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411849>Question 411849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help I am factoring polynomals and this one has me stumped!<BR>\n" );
document.write( "2x-3=8x^3-12x^2  please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289394 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "2x -3 = 8x^3 - 12x^2\r<BR>\n" );
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document.write( "=>  2x-3 = 4x^2(2x - 3)\r<BR>\n" );
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document.write( "=> 2x-3 - 4x^2(2x - 3) = 0\r<BR>\n" );
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document.write( "=> (2x-3) (1 -4x^2) = 0\r<BR>\n" );
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document.write( "=> (2x-3) (1 -(2x)^2) = 0\r<BR>\n" );
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document.write( "=> (2x-3) (1 - 2x)(1 + 2x) = 0\r<BR>\n" );
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document.write( "as a^2 -b^2 = (a+b)(a-b)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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