document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411814>Question 411814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)find three consecutive integers such that the sum of the third equels 142\r<BR>\n" );
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document.write( "2)find four consecutive intagers such that 8 times the sum of the first and the third is 40 greater than 10 times the forth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289382 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  divide by 3 so approx 47<BR>\n" );
document.write( "46 47 48  142 does not fit it should b 141\r<BR>\n" );
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document.write( "2 8*(x+x+2)=10(x+3)+40\r<BR>\n" );
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document.write( "or 16x+16=10x+30+40\r<BR>\n" );
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document.write( "or 6x =70-16=54\r<BR>\n" );
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document.write( "or x=9\r<BR>\n" );
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document.write( "digits are 9 10 11 12 </SPAN>\n" );
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