document.write( "Question 411711: Find an equation of the line containing the given point and parallel to the given line:
\n" ); document.write( "(2,5)
\n" ); document.write( "3y-x=6
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Algebra.Com's Answer #289335 by jjordan95(63)\"\" \"About 
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(2,5)
\n" ); document.write( "3y-x=6
\n" ); document.write( "=============
\n" ); document.write( "Solve for y
\n" ); document.write( "\"3y=x%2B6\"
\n" ); document.write( "\"y=%281%2F3%29x%2B2\"
\n" ); document.write( "-
\n" ); document.write( "\"y=mx%2Bb\" (m is the slope, b is the y-intercept.)
\n" ); document.write( "-
\n" ); document.write( "For a line to be parallel to the above line, the slopes need to be the same.
\n" ); document.write( "\"y=%281%2F3%29x%2Bb\"
\n" ); document.write( "-
\n" ); document.write( "Now plug in your x and y from the point you were given. (2,5), x=2, y=5.
\n" ); document.write( "\"5=%281%2F3%292%2Bb\"
\n" ); document.write( "Solve for b
\n" ); document.write( "\"5-2%2F3=b\"
\n" ); document.write( "\"15%2F3-2%2F3=b\"
\n" ); document.write( "\"13%2F3=b\"
\n" ); document.write( "-
\n" ); document.write( "Therefore, the answer is:
\n" ); document.write( "\"highlight%28y=%281%2F3%29x%2B13%2F3%29\"
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