document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411677>Question 411677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangular field is 400ft. the lenght is to be 20ft more than the width.find the lenght and width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289328 by </B><A HREF=/tutors/aboutme.mpl?userid=emargo19><B>emargo19(101)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=emargo19><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let width be x<BR>\n" );
document.write( "Let length be x+20<BR>\n" );
document.write( " Perimeter= 2(width) + 2(length)<BR>\n" );
document.write( "2(x) + 2(x+20)=400<BR>\n" );
document.write( "2x + 2x + 40 = 400<BR>\n" );
document.write( "4x = 360<BR>\n" );
document.write( "x = 90<BR>\n" );
document.write( "Width = 90 ft<BR>\n" );
document.write( "Lenth = x+ 20 = 110 ft.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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