document.write( "Question 411584: y=-2/3 x-2 how do graph using the slope y intercept? \n" ); document.write( "
Algebra.Com's Answer #289284 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"y=-%282%2F3%29x-2\"..........here, you have a slope \"m=-%282%2F3%29\" and the graph \r
\n" ); document.write( "\n" ); document.write( "of this line crosses \"y-axis\" at \"-2\"\r
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\n" ); document.write( "\n" ); document.write( "to graph it you need two points\r
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\n" ); document.write( "\n" ); document.write( "let points be : \r
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\n" ); document.write( "\n" ); document.write( "(\"0\",\"-2\").....your \"y-intercept\"...point where \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "now find your \"x-intercept\"...point where \"y=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=-%282%2F3%29x-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2F3%29x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2F%282%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-%282%2F1%29%2F%282%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-%282%2A3%29%2F%282%2A1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-%28cross%282%29%2A3%29%2F%28cross%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"x-intercept\" is at\r
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\n" ); document.write( "\n" ); document.write( "(\"-3\",\"0\")..\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-6%2C+5%2C+-10%2C+10%2C+-%282%2F3%29x-2%29+\" \r
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