document.write( "Question 411564: Please help me solve this equations,write the equations of the following ellipse in their cannonical forms and hence, determine their Foci and vertices:
\n" ); document.write( "1) 4x^2+5y^2-24x-20y+36=0
\n" ); document.write( "2) x^2+3y^2+2x-24y+46=0
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Algebra.Com's Answer #289281 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Ellipses:
\n" ); document.write( "1) 4x^2+5y^2-24x-20y+36=0
\n" ); document.write( " 4(x^2-6x) + 5(y^2-4y) +36 = 0 |completing squares
\n" ); document.write( " 4[(x-3)^2 -9] + 5[(y-2)^2 -4] + 36 = 0
\n" ); document.write( " 4(x-3)^2 -36 + 5(y-2)^2 -20 + 36 = 0
\n" ); document.write( " 4(x-3)^2 + 5(y-2)^2 = 20
\n" ); document.write( " \"+%28x-3%29%5E2%2F5+%2B+%28y-2%29%5E2+%2F4+=+1+\"
\n" ); document.write( "C(3,2) V(3,4)&V(3,0) and V(3+sqrt(5),2)&V(3-sqrt(5),2)
\n" ); document.write( " sqrt(5-4)= 1 f(4,2) and f(2,2)
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\n" ); document.write( "\n" ); document.write( "2) x^2+3y^2+2x-24y+46=0 |completing squares
\n" ); document.write( " (x+1)^2 -1 +3[(y-4)^2 -16] + 46 = 0
\n" ); document.write( " (x+1)^2 +3(y-4)^2 -49 + 46 = 0
\n" ); document.write( " \"%28x%2B1%29%5E2%2F3+%2B+%28y-4%29%5E2%2F1+=+1\"
\n" ); document.write( " C(-1,4) V(-1,5)&V(-1,3) and V(-1+sqrt(3),4)&V(-1-sqrt(3),4)
\n" ); document.write( " sqrt(3-1)=sqrt(2) f(-1 +sqrt(2),4) and f(-1-sqrt(2),4)
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