document.write( "Question 411559: Find the solution set in a +bi form: 6x^2 + 4x +1 =0\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic equation. The constants are a=6, b=4 and c=1. \r
\n" ); document.write( "\n" ); document.write( "x = -b +/-sqrt(b^2-4ac)]/12 \r
\n" ); document.write( "\n" ); document.write( "Thank you so much \n" ); document.write( "
Algebra.Com's Answer #289276 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Hi
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document.write( "Finding the solution set in a +bi form:
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document.write( "6x^2 + 4x +1 =0
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document.write( " a=6, b=4 and c=1  |Yes!
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "x = -b  ± sqrt(b^2-4ac)]/12   |Yes! Finish substituting for b, b^2 and 4ac
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document.write( "x = -4 ± sqrt(16-24)]/12
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document.write( "x = -4 ± sqrt(-8)]/12
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document.write( "x = -4 ± sqrt(-1*4*2)]/12    |sqrt(-1) = i
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document.write( "x = -4 ± 2isqrt(2)]/12
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document.write( "x = -1/3 ± (1/6)isqrt(2)
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document.write( "x = -1/3 + (1/6)isqrt(2) x = -1/3 - (1/6)isqrt(2)
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