document.write( "Question 411510: mr.stone started from home on a trip, planning to average 48 miles per hour. How fast must his son carl plan to travel in order to overtake him in 3 hours if carl started 30 minutes after his father? \n" ); document.write( "
| Algebra.Com's Answer #289250 by mananth(16946)     You can put this solution on YOUR website! mr.stone started from home on a trip, planning to average 48 miles per hour. How fast must his son carl plan to travel in order to overtake him in 3 hours if carl started 30 minutes after his father?\r \n" ); document.write( "\n" ); document.write( "stone speed = 48mph \n" ); document.write( "in 3 hours he travels 48*3=144 miles \n" ); document.write( ".. \n" ); document.write( "let son's speed be be x mph more than Stne's speed \n" ); document.write( ".. \n" ); document.write( "Son's speed = 48+x \n" ); document.write( ".. \n" ); document.write( "Father starts 1/2 hour early \n" ); document.write( "catch up distance = 24 miles \n" ); document.write( "catch up time = 3 hours \n" ); document.write( "time = distance / speed \n" ); document.write( "3=24+144/(48+x) \n" ); document.write( "3x+144 = 168 \n" ); document.write( "3x= 168-144 \n" ); document.write( "3x=24 \n" ); document.write( "x=8 \n" ); document.write( "... \n" ); document.write( "son has to travel 48+8 =56 mph.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |