document.write( "Question 411504: analyze the equation x^2+9y^2+6x-18y+9=0; that is find the center,foci,vertices, and graph
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Algebra.Com's Answer #289248 by lwsshak3(11628)\"\" \"About 
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analyze the equation x^2+9y^2+6x-18y+9=0; that is find the center,foci,vertices, and graph
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\n" ); document.write( "\n" ); document.write( "completing the squares,
\n" ); document.write( "(x^2+6x+9)+9(y^2-2y+1)=-9+9+9=9
\n" ); document.write( "(x+3)^2+9(y-1)^2=9
\n" ); document.write( "(x+3)^2/9+(y-1)^2/1=1
\n" ); document.write( "This equation is a standard form of an ellipse:(x-h)^2/a^2+(y-k)^2/b^2=1
\n" ); document.write( "Major axis is horizontal and center at (-3,1)
\n" ); document.write( "a^2=9
\n" ); document.write( "a=3
\n" ); document.write( "b^1=1
\n" ); document.write( "b=1
\n" ); document.write( "c=sqrt(a^2-b^2)=sqrt(8)=2.83
\n" ); document.write( "vertices: (-6,1) and 0,1)
\n" ); document.write( "foci: (4.83,1),(.83,1)
\n" ); document.write( "see graph below
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\n" ); document.write( "y=1+((9-(x+3)^2)/9)^.5\r
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