document.write( "Question 411449: I am now learning sum and difference of Binomials
\n" ); document.write( " (3y^2 + 1) (3y^2 - 1)
\n" ); document.write( "i have no idea how to figure it out this way.
\n" ); document.write( "

Algebra.Com's Answer #289202 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(3y^2 + 1) (3y^2 - 1)
\n" ); document.write( "-----
\n" ); document.write( "This problem involves the product of binomials.
\n" ); document.write( "The form of the problem is \"the product of the
\n" ); document.write( "sum and difference of two terms\".
\n" ); document.write( "----
\n" ); document.write( "Ans: (3y^2)^2 - 1
\n" ); document.write( "---
\n" ); document.write( "= 9y^4-1
\n" ); document.write( "==================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );