document.write( "Question 411449: I am now learning sum and difference of Binomials
\n" );
document.write( " (3y^2 + 1) (3y^2 - 1)
\n" );
document.write( "i have no idea how to figure it out this way. \n" );
document.write( "
Algebra.Com's Answer #289202 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (3y^2 + 1) (3y^2 - 1) \n" ); document.write( "----- \n" ); document.write( "This problem involves the product of binomials. \n" ); document.write( "The form of the problem is \"the product of the \n" ); document.write( "sum and difference of two terms\". \n" ); document.write( "---- \n" ); document.write( "Ans: (3y^2)^2 - 1 \n" ); document.write( "--- \n" ); document.write( "= 9y^4-1 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |