document.write( "Question 411412: how do you find the area of a right triangle if you only know the length of the hypotenuse (6)and the perimeter (14) \n" ); document.write( "
Algebra.Com's Answer #289193 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how do you find the area of a right triangle if you only know the length of the hypotenuse (6)and the perimeter (14) \n" ); document.write( "--- \n" ); document.write( "Area = base*height \n" ); document.write( "------- \n" ); document.write( "Perimeter = base + height + hypotenuse = 14 \n" ); document.write( "b + h +6 = 14 \n" ); document.write( "b + h = 8 \n" ); document.write( "b = 8-h \n" ); document.write( "b^2 = (8-h)^2 \n" ); document.write( "---- \n" ); document.write( "Using Pythagoras: \n" ); document.write( "b^2 + h^2 = 6^2 \n" ); document.write( "b^2 = 36-h^2 \n" ); document.write( "--- \n" ); document.write( "Solve for \"b\": \n" ); document.write( "(8-h)^2 = 36- h^2 \n" ); document.write( "64-16h+h^2 = 36-h^2 \n" ); document.write( "--- \n" ); document.write( "2h^2-16h+28 = 0 \n" ); document.write( "h^2-8h+14 = 0 \n" ); document.write( "--- \n" ); document.write( "h = [8 +- sqrt(64-4*14)]/2 \n" ); document.write( "--- \n" ); document.write( "h = [8 +- sqrt(8)]/2 \n" ); document.write( "--- \n" ); document.write( "Positive solution: \n" ); document.write( "h = 4+sqrt(2) \n" ); document.write( "---- \n" ); document.write( "Solve for \"b\": \n" ); document.write( "b^2 = 36-h^2 \n" ); document.write( "h^2 = (4+sqrt(2))^2 = 16+8sqrt(2)+2 = 18+8sqrt(2) \n" ); document.write( "b^2 = 36-(18+8sqrt(2) \n" ); document.write( "b^2 = 18-8sqrt(2) \n" ); document.write( "---- \n" ); document.write( "Area = (1/2)bh \n" ); document.write( "Area = (1/2)(sqrt[18-8sqrt(2)])[4+sqrt(2)] \n" ); document.write( "etc. \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========= \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( " |