document.write( "Question 411412: how do you find the area of a right triangle if you only know the length of the hypotenuse (6)and the perimeter (14) \n" ); document.write( "
Algebra.Com's Answer #289193 by stanbon(75887)\"\" \"About 
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how do you find the area of a right triangle if you only know the length of the hypotenuse (6)and the perimeter (14)
\n" ); document.write( "---
\n" ); document.write( "Area = base*height
\n" ); document.write( "-------
\n" ); document.write( "Perimeter = base + height + hypotenuse = 14
\n" ); document.write( "b + h +6 = 14
\n" ); document.write( "b + h = 8
\n" ); document.write( "b = 8-h
\n" ); document.write( "b^2 = (8-h)^2
\n" ); document.write( "----
\n" ); document.write( "Using Pythagoras:
\n" ); document.write( "b^2 + h^2 = 6^2
\n" ); document.write( "b^2 = 36-h^2
\n" ); document.write( "---
\n" ); document.write( "Solve for \"b\":
\n" ); document.write( "(8-h)^2 = 36- h^2
\n" ); document.write( "64-16h+h^2 = 36-h^2
\n" ); document.write( "---
\n" ); document.write( "2h^2-16h+28 = 0
\n" ); document.write( "h^2-8h+14 = 0
\n" ); document.write( "---
\n" ); document.write( "h = [8 +- sqrt(64-4*14)]/2
\n" ); document.write( "---
\n" ); document.write( "h = [8 +- sqrt(8)]/2
\n" ); document.write( "---
\n" ); document.write( "Positive solution:
\n" ); document.write( "h = 4+sqrt(2)
\n" ); document.write( "----
\n" ); document.write( "Solve for \"b\":
\n" ); document.write( "b^2 = 36-h^2
\n" ); document.write( "h^2 = (4+sqrt(2))^2 = 16+8sqrt(2)+2 = 18+8sqrt(2)
\n" ); document.write( "b^2 = 36-(18+8sqrt(2)
\n" ); document.write( "b^2 = 18-8sqrt(2)
\n" ); document.write( "----
\n" ); document.write( "Area = (1/2)bh
\n" ); document.write( "Area = (1/2)(sqrt[18-8sqrt(2)])[4+sqrt(2)]
\n" ); document.write( "etc.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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