document.write( "Question 411380: log8(3x-2)=2
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document.write( "log2(4x)-log2(3=6)
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document.write( "4e^2x+1=12
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document.write( "log6(x+6)+log6(2=2)
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document.write( "log3[log2(x+5)]=1
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document.write( "2log3(7)=log3(x) \n" );
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Algebra.Com's Answer #289181 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! log8(3x-2)=2 \n" ); document.write( "--- \n" ); document.write( "3x-2 = 8^2 \n" ); document.write( "3x-2 = 64 \n" ); document.write( "3x = 66 \n" ); document.write( "x = 22 \n" ); document.write( "--------------\r \n" ); document.write( "\n" ); document.write( "log2(4x)-log2(3)=6 \n" ); document.write( "log2[(4x/3)] = 6 \n" ); document.write( "4x/3 = 2^6 \n" ); document.write( "4x = 3*64 \n" ); document.write( "x = 3*16 \n" ); document.write( "x = 48 \n" ); document.write( "----------------\r \n" ); document.write( "\n" ); document.write( "4e^2x+1=12 \n" ); document.write( "e^(2x+1) = 3 \n" ); document.write( "2x+1 = ln(3) \n" ); document.write( "2x = 0.09861 \n" ); document.write( "x = 0.04931 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( "log6(x+6)+log6(2=2) \n" ); document.write( "log3[log2(x+5)]=1 \n" ); document.write( "2log3(7)=log3(x) \n" ); document.write( " \n" ); document.write( " |