document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43850>Question 43850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by any method. Assume a and b represent nonzero constants.\r<BR>\n" );
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document.write( "ax + by = 3\r<BR>\n" );
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document.write( "ax - by = 10  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28916 by </B><A HREF=/tutors/aboutme.mpl?userid=adamchapman><B>adamchapman(301)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adamchapman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ax+by=3     ..1<BR>\n" );
document.write( "ax-by=10    ..2<BR>\n" );
document.write( "adding equations (..1) and (..2) together gives:<BR>\n" );
document.write( "2ax=13          ..3<BR>\n" );
document.write( "ax=13/2=6.5     ..4<BR>\n" );
document.write( "substitute equation (..4) into (..1) to give:<BR>\n" );
document.write( "6.5+by=3<BR>\n" );
document.write( "by=-3.5\r<BR>\n" );
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document.write( "I hope this helps.\r<BR>\n" );
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document.write( "P.S. I am trying to start my own mathematics homework help website.  I would be extremely grateful if you would send me your feedback on my help to adam.chapman@student.manchester.ac.uk.  </SPAN>\n" );
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