document.write( "Question 411320: Determine the sum and product of the roots of 3y^2– 2y + 12 = 0\r
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Algebra.Com's Answer #289157 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "finding the roots using the quadratic formula
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document.write( "3y^2– 2y + 12 = 0
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document.write( "    x = -.5 + 2isqrt(35)/6
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document.write( "    x = -.5 - 2isqrt(35)/6
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document.write( "Sum of the roots = -1
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document.write( "Product: .25 + 4*35/36 
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document.write( "Note i^2 = -1 \n" );
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