document.write( "Question 411267: hi, the length of a rectangle is 6 more than its witdth, the area is 72 cm^2, find the height.\r
\n" ); document.write( "\n" ); document.write( "i did 1/2*b*h....
\n" ); document.write( "1/2(b2+4B)=30
\n" ); document.write( "b2+4b=60
\n" ); document.write( "b2+4b-60=0\r
\n" ); document.write( "\n" ); document.write( "b-6 b+10\r
\n" ); document.write( "\n" ); document.write( "b=6 b+-10\r
\n" ); document.write( "\n" ); document.write( "is the answer 6 , i am having a hard time confirmting this answer.\r
\n" ); document.write( "\n" ); document.write( "thank you in advance for your help \n" ); document.write( "

Algebra.Com's Answer #289134 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "length of a 'rectangle' is 6 more than its witdth
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document.write( "Let x and (x+6) represent the width and length respectively
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document.write( "Question states***
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document.write( " x(x+6) = 72 cm^2    |Area of a rectangle is w*l
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document.write( "Solving for x
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document.write( " x^2 + 6x - 72 = 0
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document.write( "factoring
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document.write( " (x+12)(x-6) = 0
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document.write( " (x+12) = 0  x = -12  |tossing out negative solution for a measure
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document.write( " (x -6) = 0   x = 6cm, the width.  The length is 12cm  (6cm+6)\r
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document.write( "CHECKING our Answer***
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document.write( " 6cm*12cm = 72 cm^2
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document.write( "   \r
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