document.write( "Question 409726: Hi can you please help me with this question, graph the equation equal to: 2x^2-2x-2y-1=0 and find the vertix, focus point and axis of symmetry. Thank you all your help... \n" ); document.write( "

Algebra.Com's Answer #289106 by lwsshak3(11628) $\"\"$ $\"About$

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graph the equation equal to: 2x^2-2x-2y-1=0 and find the vertex, focus point and axis of symmetry. \r
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\n" ); document.write( "\n" ); document.write( "2x^2-2x-2y-1=0
\n" ); document.write( "Standard form for parabola: (x-h)^2=4p(y-k),(h,k) being the (x,y) coordinates of the vertex,p=distance from vertex to focus or vertex to directrix(in the opposite direction) on the axis of symmetry.
\n" ); document.write( "Completing the sqare:
\n" ); document.write( "2(x^2-x+1/4)-2y=1+1/2=3/2
\n" ); document.write( "2(x-1/2)^2=2y+3/2=2(y+3/4)
\n" ); document.write( "equation in standard form:
\n" ); document.write( "(x-1/2)^2=(y+3/4)
\n" ); document.write( "axis of symmetry = x=1/2
\n" ); document.write( "vertex (1/2,-3/4)
\n" ); document.write( "4p=1
\n" ); document.write( "p=1/4
\n" ); document.write( "Directrix = y=-1
\n" ); document.write( "Focus (1/2,-1/2)\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "y=(x-.5)^2-.75\r
\n" ); document.write( "\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+%28x-.5%29%5E2-.75%29+\"$ \r
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