document.write( "Question 409738: Can you please help with the following question?\r
\n" ); document.write( "\n" ); document.write( "Given Focus is (0,2) and Directrix is y=4, find the equation of the parabola.
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Algebra.Com's Answer #289102 by lwsshak3(11628)\"\" \"About 
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Given Focus is (0,2) and Directrix is y=4, find the equation of the parabola.\r
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\n" ); document.write( "\n" ); document.write( "Since the directrix is above the focus, it is a parabola that opens downward with its axis of symmetry at x=0. The vertex is also on the axis of symmetry between the directrix and focus at (0,3) Its standard form is, (x-h)^2=4p(y-k), with (h,k) being the (x,y) coordinates of the vertex, and p=1,the distance from vertex to focus or to directrix.\r
\n" ); document.write( "\n" ); document.write( "Equation of parabola:x^2=-4(y-3)
\n" ); document.write( "see graph below:\r
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\n" ); document.write( "y=(x^2-12)/-4\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%28x%5E2-12%29%2F-4%29+\"
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