document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411216>Question 411216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. Thw formula for the perimeter of a rectangle is P=2L+2W. Set up an equation for the perimeter involving only L, the length of the rectangle. Solve this equation algebraically to find the length of the rectangle. Find the width as well. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289091 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2(L-5)=50<BR>\n" );
document.write( "2L+2L-10=50<BR>\n" );
document.write( "4L=60<BR>\n" );
document.write( "L=15<BR>\n" );
document.write( "L-5=10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );