document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411131>Question 411131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by substitution method.\r<BR>\n" );
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document.write( "8x+5y=29<BR>\n" );
document.write( "-8x+y=25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289070 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The bottom equation gives 8x = y - 25.  Substitute this into the top equation:\r<BR>\n" );
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document.write( "y - 25  + 5y = 29\r<BR>\n" );
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document.write( "6y = 54\r<BR>\n" );
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document.write( "y = 9.\r<BR>\n" );
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document.write( "==> 8x = 9 - 25\r<BR>\n" );
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document.write( "8x = -16\r<BR>\n" );
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document.write( "x = -2. </SPAN>\n" );
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