document.write( "Question 411215: I need help on this word problem.Iam enrolled in an Algebra2 course.Thank you!\r
\n" ); document.write( "\n" ); document.write( "1. Jose purchased tickets to a rock show for 8 adults and 2 children.The total cost was $132.The cost of a child's ticket was $4 less than the cost of an abult's ticket.Find the price of an adult's ticket and a child's ticket.\r
\n" ); document.write( "\n" ); document.write( "---you dont have to solve it for me.I only want the formula,and I can solve it myself.
\n" ); document.write( "x+y=132?
\n" ); document.write( "8x-4y=?iam not sure but iam trying. thank you!!
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Algebra.Com's Answer #289069 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
There is no formula. However you'll get a system of equations which will eventually reduce to one single-variable equation that is easy to solve.\r
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\n" ); document.write( "\n" ); document.write( "We can let \"a\" be the cost of an adult ticket and \"c\" be the cost of a child's ticket. Therefore \"8a+%2B+2c+=+132\". Also, the child's ticket is $4 less than an adult's ticket so \"c+=+a+-+4\". We can substitute \"c\" into the first equation to get\r
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\n" ); document.write( "\n" ); document.write( "\"8a+%2B+2%28a-4%29+=+132\", from here you can solve for a, then plug your result into \"c+=+a-4\" to find c.
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