document.write( "Question 410985: A contractor took a contract for 45 days and employed 110 workers. If they complete ¼ of work in 15 days then how many extra workers he need to complete it.
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Algebra.Com's Answer #289053 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A contractor took a contract for 45 days and employed 110 workers. If they complete ¼ of work in 15 days then how many extra workers he need to complete it. \n" ); document.write( ": \n" ); document.write( "Find how many man-days it took to do 1/4 of the job with 110 worker working 15 days. \n" ); document.write( "110*15 = 1650 man-days to completed 1/4 of the job \n" ); document.write( "then \n" ); document.write( "3 * 1650 = 4950 man-days required to do the remaining 3/4 of the job \n" ); document.write( ": \n" ); document.write( "Complete job requires 4 * 1650 = 6600 man-days \n" ); document.write( ": \n" ); document.write( "Let x = no. of extra workers required to finish in the remaining 30 days of the contract \n" ); document.write( "30(x+110) = 4950 \n" ); document.write( "30x + 3300 = 4950 \n" ); document.write( "30x = 4950 - 3300 \n" ); document.write( "30x = 1650 \n" ); document.write( "x = \n" ); document.write( "x = 55 more workers needed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( "110*15 = 1650 man-days \n" ); document.write( "165*30 = 4950 man-days \n" ); document.write( "------------------------ \n" ); document.write( "complete job: 6600 man-days\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |