document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411199>Question 411199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the maximum or minimum value of the function. <BR>\n" );
document.write( "f(x)= -x^2/3+2x+6  (it's -x^2 over 3 then +2x+6)<BR>\n" );
document.write( " <BR>\n" );
document.write( "I thought that you have to use -b/2a and then f(x)=-b/2a      <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289052 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the maximum or minimum value of the function. <BR>\n" );
document.write( "f(x)= -x^2/3+2x+6 (it's -x^2 over 3 then +2x+6)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "a = (-1/3) ; b = 2 ; c = 6<BR>\n" );
document.write( "----<BR>\n" );
document.write( "I thought that you have to use -b/2a and then f(x)=-b/2a <BR>\n" );
document.write( "Max or min occurs at x = -b/(2a) = -2/(2*(-1/3)) = -2/(-2/3) = 3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "f(3) = (-1/3)(3^2) + 2(3) + 6 <BR>\n" );
document.write( "= -3+6+6<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= 9<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=========== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );