document.write( "Question 411074: (log base of 3)3+(log base of 3)x=5 \n" ); document.write( "
Algebra.Com's Answer #288958 by Tatiana_Stebko(1539)\"\" \"About 
You can put this solution on YOUR website!
\"log%283%2C3%29%2Blog%283%2Cx%29=5\"
\n" ); document.write( "Use formulas \"log%28c%2Ca%29%2Blog%28c%2Cb%29=log%28c%2C%28ab%29%29\", so \"log%283%2C3%29%2Blog%283%2Cx%29=log%283%2C3x%29\"
\n" ); document.write( "__________\"a=%28log%28c%2Cc%5Ea%29%29\", so \"5=log%283%2C3%5E5%29=log%283%2C+243%29\"
\n" ); document.write( "\"log%283%2C3x%29=log%283%2C243%29\"
\n" ); document.write( "\"3x=243\"
\n" ); document.write( "\"x=243%2F3\"
\n" ); document.write( "\"x=81\"
\n" ); document.write( ".
\n" ); document.write( "Check the answer
\n" ); document.write( "\"log%283%2C3%29%2Blog%283%2C81%29=5\"
\n" ); document.write( "\"1%2B4=5\"
\n" ); document.write( "\"5=5\"- correct
\n" ); document.write( "Answer x=81
\n" ); document.write( "
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