document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411064>Question 411064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I think I did this quadratic equation right. would you please check it?  I think I reduced it right.\r<BR>\n" );
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document.write( "x^2+4x+7=0\r<BR>\n" );
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document.write( "-4+-sqrt((4)^2-4(1)(7))/(2(1))<BR>\n" );
document.write( "-4+-sqrt(16-28)/(2)<BR>\n" );
document.write( "-4+-sqrt(-12)/(2)<BR>\n" );
document.write( "-4+-sqrt(4(3)i)/(2)<BR>\n" );
document.write( "-4+- 2 sqrt(3i)/(2)<BR>\n" );
document.write( "-2+- 1 sqrt(3i)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288948 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You did it right, but got the terminology off at the end.\r<BR>\n" );
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document.write( "It's -2 ± i*sqrt(3)<BR>\n" );
document.write( "Or x = -2 ± sqrt(3)*i\r<BR>\n" );
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document.write( "The i can't be under the radical.<BR>\n" );
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