document.write( "Question 411026: Hi, I do not understand how to reduce or when to reduce the fraction within the quadratic equation. I came up with this answer. Would you please show me how to reduce for the final answer? Thanks.\r
\n" ); document.write( "\n" ); document.write( "-x^2+6x-21=0\r
\n" ); document.write( "\n" ); document.write( "(-1)-x^2+6x-21=0(-1)\r
\n" ); document.write( "\n" ); document.write( "x^2+6x-21=0\r
\n" ); document.write( "\n" ); document.write( "-6+-sqrt((6)^2-4(1)(-21))/2(1)
\n" ); document.write( "-6+-sqrt(36+84)/(2)
\n" ); document.write( "-6+-sqrt(120)/(2)
\n" ); document.write( "-6+-sqrt(6(20))/(2)
\n" ); document.write( "-6+-sqrt(6)/(2)
\n" ); document.write( "-6+- 20 sqrt(6)/(2)
\n" ); document.write( "-?+- sqrt(6)/(10) (thought we divide -6/20 then divide 2/20) leaves the 6
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Algebra.Com's Answer #288921 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "As important as correctly using the quadratic formula is starting with the
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document.write( "correct quadratic equation to apply it to:
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document.write( "-x^2+6x-21=0    |Must multiply ALL terms by -1 to proceed in tha fashion
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document.write( " x^2 - 6x + 21 = 0
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document.write( "x^2+6x-21=0   |If... this were the correct quadratic (using as an example)
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document.write( "-6+-sqrt(120)/(2)
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document.write( "-6+-sqrt(4*30)/(2)
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document.write( "-6+-2sqrt(30)/(2)
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document.write( "-3+-sqrt(30)   |important to take the 'sqrt(4)out front'\r
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