document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=411026>Question 411026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I do not understand how to reduce or when to reduce the fraction within the quadratic equation.  I came up with this answer.  Would you please show me how to reduce for the final answer?  Thanks.\r<BR>\n" );
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document.write( "-x^2+6x-21=0\r<BR>\n" );
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document.write( "(-1)-x^2+6x-21=0(-1)\r<BR>\n" );
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document.write( "x^2+6x-21=0\r<BR>\n" );
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document.write( "-6+-sqrt((6)^2-4(1)(-21))/2(1)<BR>\n" );
document.write( "-6+-sqrt(36+84)/(2)<BR>\n" );
document.write( "-6+-sqrt(120)/(2)<BR>\n" );
document.write( "-6+-sqrt(6(20))/(2)<BR>\n" );
document.write( "-6+-sqrt(6)/(2)<BR>\n" );
document.write( "-6+- 20 sqrt(6)/(2)<BR>\n" );
document.write( "-?+- sqrt(6)/(10) (thought we divide -6/20  then divide 2/20) leaves the 6<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288918 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=-1, b=6, c=-21<BR>\n" );
document.write( "x=(-6+-sqrt(36-4*21))/-2 not /2 and not -4(1)(-21) should be -4(-1)(-21)<BR>\n" );
document.write( "=(-6+-sqrt(-48))/-2<BR>\n" );
document.write( "=(-6+-4sqrt(3)i)/-2<BR>\n" );
document.write( "=3+-2sqrt(3)i<BR>\n" );
document.write( "=3+2sqrt(3)i, =3-2sqrt(3)i<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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