document.write( "Question 411024: I am having trouble reducing the fraction within the quadratic equation. Would you please check my process to see if I did it right and help me with the ending part?\r
\n" ); document.write( "\n" ); document.write( "(4x-3)^2=0\r
\n" ); document.write( "\n" ); document.write( "(4x-3)(4x-3)=0
\n" ); document.write( "16x^2-12x-12x-9=0
\n" ); document.write( "16x^2-24x-9=0\r
\n" ); document.write( "\n" ); document.write( "-24+- sqrt((24)^2-4(16)(-9))/(2(16))
\n" ); document.write( "-24+- sqrt(576+576)/(32)
\n" ); document.write( "-24+- sqrt(1152)/(32)
\n" ); document.write( "-24+- sqrt(8(144))/(32)
\n" ); document.write( "-24+- sqrt(4(2)(144))/(32)
\n" ); document.write( "-24+- 12(2) sqrt(2)/(32)
\n" ); document.write( "-24+- 24 sqrt(2)/(32)
\n" ); document.write( "-1+- sqrt(3(1)/(3)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #288915 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Hi
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document.write( "IF: 16x^2-24x-9=0  
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document.write( "THEN: 
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "\"x+=+%2824+%2B-+sqrt%28+1152+%29%29%2F%2832%29+\"
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document.write( "[24 ± 24sqrt(2)]/(32)  = 3/4 ± (3/4)sqrt(2)\r
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document.write( "However, in this question: (4x-3)(4x-3)=0  | 16x^2-24x+9=0 
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document.write( "\"x+=+%2824+%2B-+sqrt%28+0+%29%29%2F%2832%29+\"
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document.write( " x = 3/4 
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