document.write( "Question 411024: I am having trouble reducing the fraction within the quadratic equation. Would you please check my process to see if I did it right and help me with the ending part?\r
\n" ); document.write( "\n" ); document.write( "(4x-3)^2=0\r
\n" ); document.write( "\n" ); document.write( "(4x-3)(4x-3)=0
\n" ); document.write( "16x^2-12x-12x-9=0
\n" ); document.write( "16x^2-24x-9=0\r
\n" ); document.write( "\n" ); document.write( "-24+- sqrt((24)^2-4(16)(-9))/(2(16))
\n" ); document.write( "-24+- sqrt(576+576)/(32)
\n" ); document.write( "-24+- sqrt(1152)/(32)
\n" ); document.write( "-24+- sqrt(8(144))/(32)
\n" ); document.write( "-24+- sqrt(4(2)(144))/(32)
\n" ); document.write( "-24+- 12(2) sqrt(2)/(32)
\n" ); document.write( "-24+- 24 sqrt(2)/(32)
\n" ); document.write( "-1+- sqrt(3(1)/(3)\r
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Algebra.Com's Answer #288914 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
16x^2-24x+9=0 not -9
\n" ); document.write( "x=(24+-sqrt(576-4*16*9))/32 not -24
\n" ); document.write( "=(24+-sqrt(0))/32
\n" ); document.write( "=24/32
\n" ); document.write( "=3/4
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\n" ); document.write( "Ed
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