document.write( "Question 411024: I am having trouble reducing the fraction within the quadratic equation. Would you please check my process to see if I did it right and help me with the ending part?\r
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document.write( "(4x-3)^2=0\r
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document.write( "(4x-3)(4x-3)=0
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document.write( "16x^2-12x-12x-9=0
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document.write( "16x^2-24x-9=0\r
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document.write( "-24+- sqrt((24)^2-4(16)(-9))/(2(16))
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document.write( "-24+- sqrt(576+576)/(32)
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document.write( "-24+- sqrt(1152)/(32)
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document.write( "-24+- sqrt(8(144))/(32)
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document.write( "-24+- sqrt(4(2)(144))/(32)
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document.write( "-24+- 12(2) sqrt(2)/(32)
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document.write( "-24+- 24 sqrt(2)/(32)
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document.write( "-1+- sqrt(3(1)/(3)\r
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Algebra.Com's Answer #288914 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 16x^2-24x+9=0 not -9 \n" ); document.write( "x=(24+-sqrt(576-4*16*9))/32 not -24 \n" ); document.write( "=(24+-sqrt(0))/32 \n" ); document.write( "=24/32 \n" ); document.write( "=3/4 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |