document.write( "Question 410977: Please find the area of a rectangle whose length is 21 cm and whose perimeter is 90 cm. \n" ); document.write( "
Algebra.Com's Answer #288891 by dudeantariksh(10)![]() ![]() ![]() You can put this solution on YOUR website! hiee there.. \n" ); document.write( "firstly.. \n" ); document.write( "we know that in a rectangle , the opposite sides are equal...................... \n" ); document.write( "we also know that area of a rectangle is (length) x (breadth) \n" ); document.write( "so if we find the breadth then we can easily compute the area. \n" ); document.write( "................................................................................ \n" ); document.write( "perimeter of any figure is the sum of the lenghts of all sides.. \n" ); document.write( "therefore, \n" ); document.write( "perimeter of a rectangle = lenghth + length +breadth + breadth \n" ); document.write( " = 2(length + breadth) \n" ); document.write( " = 2( 21 + breadth) \n" ); document.write( "................................................................................ \n" ); document.write( "but perimeter of the rectangle is 90 cm \n" ); document.write( " therefore, \n" ); document.write( " 90 = 2(21+breadth) \n" ); document.write( " therefore, if we divide by 2 throughout, we get, \n" ); document.write( " 90/2 = 2/2( 21+ breadth) \n" ); document.write( " therefore, \n" ); document.write( " 45 = 21 + breadth \n" ); document.write( "therefore, breadth = 45-21 (subtracting 21 from both sides) \n" ); document.write( " breadth = 24 cm. \n" ); document.write( "................................................................... \n" ); document.write( "area of the rectangle = length x breadth \n" ); document.write( " = 21 x 24 \n" ); document.write( " = 504 sq. cm.\r \n" ); document.write( "\n" ); document.write( "ans.. the area of the rectangle is 504 sq.cm. \n" ); document.write( " |