document.write( "Question 410977: Please find the area of a rectangle whose length is 21 cm and whose perimeter is 90 cm. \n" ); document.write( "
Algebra.Com's Answer #288891 by dudeantariksh(10)\"\" \"About 
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hiee there..
\n" ); document.write( "firstly..
\n" ); document.write( "we know that in a rectangle , the opposite sides are equal......................
\n" ); document.write( "we also know that area of a rectangle is (length) x (breadth)
\n" ); document.write( "so if we find the breadth then we can easily compute the area.
\n" ); document.write( "................................................................................
\n" ); document.write( "perimeter of any figure is the sum of the lenghts of all sides..
\n" ); document.write( "therefore,
\n" ); document.write( "perimeter of a rectangle = lenghth + length +breadth + breadth
\n" ); document.write( " = 2(length + breadth)
\n" ); document.write( " = 2( 21 + breadth)
\n" ); document.write( "................................................................................
\n" ); document.write( "but perimeter of the rectangle is 90 cm
\n" ); document.write( " therefore,
\n" ); document.write( " 90 = 2(21+breadth)
\n" ); document.write( " therefore, if we divide by 2 throughout, we get,
\n" ); document.write( " 90/2 = 2/2( 21+ breadth)
\n" ); document.write( " therefore,
\n" ); document.write( " 45 = 21 + breadth
\n" ); document.write( "therefore, breadth = 45-21 (subtracting 21 from both sides)
\n" ); document.write( " breadth = 24 cm.
\n" ); document.write( "...................................................................
\n" ); document.write( "area of the rectangle = length x breadth
\n" ); document.write( " = 21 x 24
\n" ); document.write( " = 504 sq. cm.\r
\n" ); document.write( "\n" ); document.write( "ans.. the area of the rectangle is 504 sq.cm.
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