document.write( "Question 410914: Using only quarters, dimes, and nickels, how many different
\n" );
document.write( "combinations of coins can be used to make 75 cents.\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #288890 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Using only quarters, dimes, and nickels, how many different \r\n" ); document.write( "combinations of coins can be used to make 75 cents.\r\n" ); document.write( "\r\n" ); document.write( "If you don't use any quarters you have to have an odd number\r\n" ); document.write( "of nickels. That could be any of the odd numbers from 1 through 15\r\n" ); document.write( "nickels, because you could always make the rest of the 75 cents with\r\n" ); document.write( "dimes only. That's 8 ways.\r\n" ); document.write( "\r\n" ); document.write( "If you use exactly 1 quarter, you have to make the remaining 50 cents\r\n" ); document.write( "using nickels and dimes and you must have an even number of nickels, from\r\n" ); document.write( "0 through 10, for you could always make the rest of the 50 cents with\r\n" ); document.write( "dimes. That's 6 more ways.\r\n" ); document.write( "\r\n" ); document.write( "If you use 2 quarters, then there are only 3 ways to make the remaining\r\n" ); document.write( "25 cents with nickels and dimes. That is 2 dimes and a nickel, 3 nickels\r\n" ); document.write( "and 1 dime, and 5 nickels. That's 3 more ways.\r\n" ); document.write( "\r\n" ); document.write( "Finally there is the one way to use 3 quarters.\r\n" ); document.write( "\r\n" ); document.write( "That's a total of 8+6+3+1 = 18 ways.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |