document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43966>Question 43966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a couple more problems today I need steps and solutions for if anyone would be so kind. \r<BR>\n" );
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document.write( "Factor each polynomial completely, given that the binomial following it is a factor of the polynomial.\r<BR>\n" );
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document.write( "x³ + 2x² - 5x – 6,  x + 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28887 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since you know x+3 is a factor, we can divide the original polynomial by it to find the \"deressed\" polynomial...that can be done either by long division or by synthetic division...in either case we get<BR>\n" );
document.write( "x^2 - x - 2 = 0 and<BR>\n" );
document.write( "(x - 2)(x + 1) = 0<BR>\n" );
document.write( "x = 2 or x = -1 </SPAN>\n" );
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