document.write( "Question 410893: the width of a rectangularrug is 3 feet. if the perimeter is 20 feet, what is the area of the area of the rug \n" ); document.write( "
Algebra.Com's Answer #288862 by richard1234(7193)\"\" \"About 
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The phrase \"area of the area of the rug\" somewhat bewilders me...\r
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\n" ); document.write( "\n" ); document.write( "Anyway, using \"P+=+2%28L%2BW%29\", substituting P = 20 and W = 3,\r
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\n" ); document.write( "\n" ); document.write( "\"20+=+2%28L%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"10+=+L%2B3\" --> \"L+=+7\". The length is 7 and the width is 3, so the area A is \"A+=+LW+=+7%2A3+=+21\" (sq feet).
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