document.write( "Question 410826: I am solving a quadratic equation. I think I have done it right, but I am not sure how to write the final answer. Would you please check my work?\r
\n" ); document.write( "\n" ); document.write( "5x^2+22=-10x\r
\n" ); document.write( "\n" ); document.write( " +10x -10x+10x
\n" ); document.write( "5x^2+22+10x=0
\n" ); document.write( " a c b\r
\n" ); document.write( "\n" ); document.write( "-10+-sqrt((10)^2-4(5)(22)/2(5)
\n" ); document.write( "-10+-sqrt(100-(-440))/(10)
\n" ); document.write( "-10+-sqrt(500)/(10)
\n" ); document.write( "-10+-sqrt(5(100))/(10)
\n" ); document.write( "-10+-10sqrt(5)/(10)
\n" ); document.write( "1+-sqrt(5)/(1)
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Algebra.Com's Answer #288813 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
Not quite. You have a sign error in the following steps:\r
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\n" ); document.write( "\n" ); document.write( "-10+-sqrt((10)^2-4(5)(22)/2(5)
\n" ); document.write( "-10+-sqrt(100-(-440))/(10) <--- should be 100 - 440, not 100 - (-440). Also, 100 - (-440) = 540, not 500.\r
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\n" ); document.write( "\n" ); document.write( "By the quadratic formula, \"x+=+%28-10+%2B-+sqrt%28100+-+440%29%29%2F10+=+%28-10+%2B-+sqrt%28-340%29%29%2F10\". We can factor 4 out of \"sqrt%28-340%29\" to obtain \"2sqrt%28-85%29\". This becomes\r
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\n" ); document.write( "\n" ); document.write( "In addition, it is more conventional (and less likely to make a mistake) to write the quadratic as \"5x%5E2+%2B+10x+%2B+22\" instead of \"5x%5E2+%2B+22+%2B+10x\".\r
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