document.write( "Question 410793: You are choosing between tow plans at a discount warehouse. Plan A offers an annual membership fee of $300 and you pay 70% of the manufacturer’s recommended list price. Plan B offers an annual membership fee of $40 and you pay 90% of the manufacturer’s recommended listed price. How many dollars of merchandise would you have to purchase in a year to pay the same amount under both plans? What will be the cost of each plan?\r
\n" ); document.write( "\n" ); document.write( "I was absent the day of class and basically I was told by a class mate to take both plan A and plan B, set them equal to each other and solve. Also Prove. I do not have the text book, money is short for me now. Please help. A step by step action so I can go about the rest of this homework. Thank you :)!
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Algebra.Com's Answer #288798 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
You are choosing between two plans at a discount warehouse.
\n" ); document.write( "Plan A offers an annual membership fee of $300 and you pay 70% of the manufacturer’s recommended list price.
\n" ); document.write( "A(x) = 300 + 0.7x where x is cost of purchased products.\r
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\n" ); document.write( "Plan B offers an annual membership fee of $40 and you pay 90% of the cost of purchased products.
\n" ); document.write( "B(x) = 40 + 0.90x
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\n" ); document.write( "\n" ); document.write( "How many dollars of merchandise would you have to purchase in a year to pay the same amount under both plans?
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "300 + 0.70x = 40 + 0.90x
\n" ); document.write( "0.20x = 260
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\n" ); document.write( "x = $1300
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\n" ); document.write( "\n" ); document.write( "What will be the cost of each plan?
\n" ); document.write( "A(1300) = 300+ 0.7*1300 = $1210
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\n" ); document.write( "B(1300) = 40 + 0.9*1300 = $1210
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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