document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=410763>Question 410763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am totally lost please help. Solving by substitution or elimination<BR>\n" );
document.write( "2x+y=6<BR>\n" );
document.write( "x-y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288776 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Basic outline:\r<BR>\n" );
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document.write( "Add the two equations to get:  \r<BR>\n" );
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document.write( "2x+y=6<BR>\n" );
document.write( "x-y=3<BR>\n" );
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document.write( "3x+0y=9\r<BR>\n" );
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document.write( "which gives us the new equation  3x=9\r<BR>\n" );
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document.write( "Next solve for x. Once you have the solution for x, use it to find y. You do this by plugging that value of x into either equation and solving for y. </SPAN>\n" );
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