document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=410550>Question 410550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 2 consecutive odd integers such that 6 times the first is 10 more than 4 time the second </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288696 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let (2x+1) = the first odd number then the next consecutive odd number will be (2x+1)+2 = (2x+3) <BR>\n" );
document.write( "Notice that whatever value you may assign to x, 2x+1 will always be odd.<BR>\n" );
document.write( "6(2x+1) = 4(2x+3)+10 \"...6 times the first is 10 more than 4 times the second.\"<BR>\n" );
document.write( "Simplify and solve for x.<BR>\n" );
document.write( "(12x+6) = (8x+12)+10 Combine like-terms. Subtract 8x from both sides.<BR>\n" );
document.write( "4x+6 = 12+10 Subtract 6 from both sides.<BR>\n" );
document.write( "4x = 16 Finally, divide by 4.<BR>\n" );
document.write( "x = 4 and...<BR>\n" );
document.write( "2x+1 = 2(4)+1 = 9<BR>\n" );
document.write( "2x+3 = 2(4)+3 = 11<BR>\n" );
document.write( "The two numbers are: 9 and 11<BR>\n" );
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