document.write( "Question 43849: Solve the system by substitution.\r
\n" ); document.write( "\n" ); document.write( "x + y = -7\r
\n" ); document.write( "\n" ); document.write( "x - y = 13
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Algebra.Com's Answer #28864 by adamchapman(301)\"\" \"About 
You can put this solution on YOUR website!
x+y=-7 ..1
\n" ); document.write( "x-y=13 ..2
\n" ); document.write( "rearrange equation(..2) to give:
\n" ); document.write( "y=x-13 ..3
\n" ); document.write( "now substitute equation (..3) into equation (..1) for y:
\n" ); document.write( "x+(x-13)=-7
\n" ); document.write( "2x-13=-7
\n" ); document.write( "2x=6
\n" ); document.write( "x=3 ..4
\n" ); document.write( "now substitute equation (..4) into equation (..3) for y:
\n" ); document.write( "y=3-13
\n" ); document.write( "y=-10\r
\n" ); document.write( "\n" ); document.write( "Therefore x=3 and y=-10\r
\n" ); document.write( "\n" ); document.write( "I hope this helps. If you have any other problems, please dont hesitate to contact me at adam.chapman@student.manchester.ac.uk
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