document.write( "Question 410515: f(x)=5x-4 and g(x)=x^2+3. Find the following:
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document.write( "(g-f)(x)
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document.write( "(fg)(x)
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document.write( "domain of g/f \n" );
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Algebra.Com's Answer #288634 by Theo(13342)![]() ![]() You can put this solution on YOUR website! (g-f)(x) \n" ); document.write( "= g(x) - f(x) \n" ); document.write( "= (x^2 + 3) - (5x - 4) \n" ); document.write( "= x^2 + 3 - 5x + 4 \n" ); document.write( "= x^2 - 5x + 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) \n" ); document.write( "= f(x) * g(x) \n" ); document.write( "= (5x-4) * (x^2 + 3) \n" ); document.write( "= 5x^3 + 15x - 4x^2 - 12 \n" ); document.write( "= 5x^3 - 4x^2 + 15x - 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(g/f)(x) \n" ); document.write( "= g(x) / f(x) \n" ); document.write( "= (x^2 + 3) / (5x-4) \n" ); document.write( "the denominator = 0 when 5x-4 = 0 \n" ); document.write( "this occurs when x = 4/5 \n" ); document.write( "the function is undefined when the denominator is equal to 0 \n" ); document.write( "the domain is therefore all real values of x except when x = 4/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph of this equation looks like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you draw a vertical line at x = 4/5, you will see that the graph of the function approaches that line but never touches it. that means that the line x = 4/5 is an asymptote of the function which also means that that the function is undefined at x = 4/5.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |