document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=410102>Question 410102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the systems of equations by the substitution method:\r<BR>\n" );
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document.write( "y=9x+7\r<BR>\n" );
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document.write( "3x-2y=1\r<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Vanessa </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288616 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the systems of equations by the substitution method:<BR>\n" );
document.write( "y = 9x + 7<BR>\n" );
document.write( "3x - 2y = 1 <BR>\n" );
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document.write( "This isn't hard, we know y = (9x+7), replace y with this in the 2nd equation:<BR>\n" );
document.write( "3x - 2(9x+7) = 1<BR>\n" );
document.write( "3x - 18x - 14 = 1<BR>\n" );
document.write( "-15x = 1 + 14<BR>\n" );
document.write( "-15x = 15<BR>\n" );
document.write( "x = -1<BR>\n" );
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document.write( "I'll let you find y, use the 1st equation, replace x with -1<BR>\n" );
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document.write( "Check your solutions in the 2nd equation </SPAN>\n" );
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