document.write( "Question 406920: How do I find a solution for :\r
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document.write( "Log base of 10 4x - log base of 10 (12 + square root of x) = 2 \n" );
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Algebra.Com's Answer #288576 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Log base of 10 4x - log base of 10 (12 + square root of x) = 2\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "log4x-log(12+sqrt(x)=2 \n" ); document.write( "applying division rule, \n" ); document.write( "log(4x/(12+sqrt(x)=2 \n" ); document.write( "convert to exponential form (the base raised to the logarithm of the number is equal to the number. In this case the base=10, the logarithm of the number=2, and the number is (4x/(12+sqrt(x)) \n" ); document.write( "4x/(12+sqrt(x)=10^2=100 \n" ); document.write( "4x=1200+100sqrt(x) \n" ); document.write( "x=300+25sqrt(x) \n" ); document.write( "x-25sqrt(x)-300=0 \n" ); document.write( "let u=sqrt(x) \n" ); document.write( "then u^2=x \n" ); document.write( "u^2-25u-300=0 \n" ); document.write( "using quadratic formula to solve, \n" ); document.write( "a=1,b=-25,c=-300 \n" ); document.write( "u=-(-25)+-sqrt((-25)^2-4(1)(-300))/2(1) \n" ); document.write( "u=(25+-sqrt(1825))/2 \n" ); document.write( "u=(25+-42.72)/2 \n" ); document.write( "u=33.86 \n" ); document.write( "u=-8.86 (reject, in log x, x>0 \n" ); document.write( "x=u^2=(33.86)^2=1146.5\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "log4x-log(12+sqrt(x) \n" ); document.write( "log(4*1146.5)-log(12+sqrt(1146.5) \n" ); document.write( "log(4586)-log(45.86) \n" ); document.write( "=3.66-1.66=2=right-hand side\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |