document.write( "Question 406920: How do I find a solution for :\r
\n" ); document.write( "\n" ); document.write( "Log base of 10 4x - log base of 10 (12 + square root of x) = 2
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Algebra.Com's Answer #288576 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Log base of 10 4x - log base of 10 (12 + square root of x) = 2\r
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\n" ); document.write( "\n" ); document.write( "log4x-log(12+sqrt(x)=2
\n" ); document.write( "applying division rule,
\n" ); document.write( "log(4x/(12+sqrt(x)=2
\n" ); document.write( "convert to exponential form (the base raised to the logarithm of the number is equal to the number. In this case the base=10, the logarithm of the number=2, and the number is (4x/(12+sqrt(x))
\n" ); document.write( "4x/(12+sqrt(x)=10^2=100
\n" ); document.write( "4x=1200+100sqrt(x)
\n" ); document.write( "x=300+25sqrt(x)
\n" ); document.write( "x-25sqrt(x)-300=0
\n" ); document.write( "let u=sqrt(x)
\n" ); document.write( "then u^2=x
\n" ); document.write( "u^2-25u-300=0
\n" ); document.write( "using quadratic formula to solve,
\n" ); document.write( "a=1,b=-25,c=-300
\n" ); document.write( "u=-(-25)+-sqrt((-25)^2-4(1)(-300))/2(1)
\n" ); document.write( "u=(25+-sqrt(1825))/2
\n" ); document.write( "u=(25+-42.72)/2
\n" ); document.write( "u=33.86
\n" ); document.write( "u=-8.86 (reject, in log x, x>0
\n" ); document.write( "x=u^2=(33.86)^2=1146.5\r
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\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "log4x-log(12+sqrt(x)
\n" ); document.write( "log(4*1146.5)-log(12+sqrt(1146.5)
\n" ); document.write( "log(4586)-log(45.86)
\n" ); document.write( "=3.66-1.66=2=right-hand side\r
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