document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43943>Question 43943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that y varies inversely as x. If y = 4 when x = 1/2, find y when x = 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28856 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The inverse relationship is written as <BR>\n" );
document.write( "y = k/x<BR>\n" );
document.write( "Now plug in to find k...<BR>\n" );
document.write( "4 = k/(1/2) and<BR>\n" );
document.write( "k = 2<BR>\n" );
document.write( "Now rewrite it with the new k and the new data to find y...<BR>\n" );
document.write( "y = 2/x<BR>\n" );
document.write( "y = 2/2<BR>\n" );
document.write( "y = 1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );